PSN-L Email List Message

Subject: Ball pivot
From: "Randall Pratt" rpratt@.............
Date: Mon, 25 Nov 2002 00:08:08 -0600


Chris,

In rolling contact the center of rotation of the ball will be the center =
of the ball and it will be in translation.  The instantanious center of =
rotation of the total boom will be the contact point. (wheel and axle)  =
If the compressive force in the boom is axial then any deflection from =
center will throw the force off axis. There will have to be contact =
friction sufficient to prevent the rotated boom from sliding on the =
plate since the boom is no longer perpendicular and this force will be =
tangent to the ball.  The friction force will be in the direction of =
pushing the boom toward center. =20
As to my earlier thought that the axis will be offset, I calculate that =
for a 24" boom and .125" motion the pivot will move .0003" left or right =
using a .125" ball.  With 12" between upper and lower pivot this would =
be less than 1% of the tilt angle you suggested and may not be a =
significant factor. =20
May I suggest an experiment for the proponents of the ball?  Operate =
with as little damping as possible and compare to a true sine wave =
equally damped.  If the ball pivot is somehow causing stability with a =
restoring force it should alter the peaks of the sine wave.  =20







Chris,
 
In rolling contact the center of = rotation of the=20 ball will be the center of the ball and it will be in translation.  = The=20 instantanious center of rotation of the total boom will be the contact=20 point. (wheel and axle)  If the compressive force in the boom = is axial=20 then any deflection from center will throw the force off axis. There = will have=20 to be contact friction sufficient to prevent the rotated boom from = sliding on=20 the plate since the boom is no longer perpendicular and this force will = be=20 tangent to the ball.  The friction force will be in the direction = of=20 pushing the boom toward center. 
As to my earlier thought that the axis = will be=20 offset, I calculate that for a 24" boom and .125" motion the pivot will = move=20 ..0003" left or right using a .125" ball.  With 12" between upper = and lower=20 pivot this would be less than 1% of the tilt angle you suggested and=20 may not be a significant factor. 
May I suggest an experiment for the = proponents of=20 the ball?  Operate with as little damping as possible and = compare to a=20 true sine wave equally damped.  If the ball pivot is somehow = causing=20 stability with a restoring force it should alter the peaks of the = sine=20 wave.   

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