PSN-L Email List Message

Subject: Re: Zero-length spring
From: John or Jan Lahr JohnJan@........
Date: Sat, 02 Dec 2006 08:25:43 -0800


Thanks, Jerry.

A Newton is a unit of force.  One Newton is approximately the 
attractive force between a 3.6 ounce object and the Earth at the 
surface of the earth.  An ounce is technically a unit of mass, not a 
unit of force.  An ounce of material is still an ounce whether it's 
located near the surface of the Earth or on the surface of the 
Moon.  The attractive force between an ounce of material at the 
Earth's surface and the earth (the weight as measured on a scale) is 
called an ounce-force.

Hope this helps!

Cheers,
John

At 06:50 AM 12/2/2006, you wrote:
>Try the Wikipedia for a 
>definition: 
>http://en.wikipedia.org/wiki/Newton 
>Of course, John can answer too.
>
>Best Wishes,
>Jerry Payton
>----- Original Message -----
>From: chief.cook.nz
>To: psn-l@..............
>Sent: Saturday, December 02, 2006 8:30 AM
>Subject: Re: Zero-length spring
>
>Hi John
>In this formula a NEWTON is what?  or how or why is called a NEWTON the rest
>I understand so a
>
>NEWTON:- =
>
>Cheers Tamati
> From the Castle of Tamati, Hinemoa and Karauwa the Dog
> From the Castle of Tom, Robyn and the Dog
>
>I'm Just a Stone's Throw Away:- NZ-021-150-33-59 or NZ-07-855-0195
>                               Bush Telegragh:- 
> chief.cook.nz@............
>                        My Regular Pitstop:- Tamati
>                                                                   P.O.BOX
>19-356 CENTRAL
>                                                                   HAMILTON
>                                                                   NEW
>ZEALAND
>----- Original Message -----
>From: "John or Jan Lahr" <JohnJan@........>
>To: <psn-l@..............>
>Sent: Thursday, November 30, 2006 8:20 PM
>Subject: Re: Zero-length spring
>
>
> > At 10:29 PM 11/29/2006, you wrote:
> >>Hi John,  I am not too good at math, could you please plug-in some
> >>examples/numbers for this formula so I can understand it better? I think
> >>its k that I am unclear of.  I understand the rest. Thanks, Ted
> >>MgA = kSY/(SA)
> >>
> >>M = kY/(Ag)
> >
> > k is the spring constant.  In this example I'm using k = 2 newtons/cm
> >
> > M is the mass
> > Y is the height of the mast
> > A is the length of the boom
> > g is the acceleration of gravity
> >
> > The exact numbers don't really matter - the point being that the mass will
> > be stable at any angle of the boom.
> >
> > There are problems of trying to actually build this device, because slight
> > changes in k with temperature will cause instability.  Even without a
> > zero-length spring, one can extend the period by reducing the height of
> > the mast.  However, you will soon discover that this will also lead to
> > instability if pushed to too long a period.
> >
> > Cheers,
> > John
> >
> >
> >
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