PSN-L Email List Message
Subject: Re: Glass?
From: ChrisAtUpw@.......
Date: Mon, 12 Nov 2007 12:07:26 EST
In a message dated 12/11/2007, tchannel1@............ writes:
Hi Folks, Just wondering about materials for roller on roller or balls on
plates. I know the limitations of glass, but a question about its
smoothness, is the surface of glass as smooth or smoother than these hardened and
polished steels?
Hi Ted,
Probably about the same. You get an optical finish with fine polish on
metal. However glass is a rapidly solidified liquid.
My second question is one of friction: If you have one ball on one plate you
would have one point of friction. If you have one ball resting between two
rollers, (in the V) you would have two points of friction, but the load would
be divided, because its resting on two points, so is the end result of
friction loss the same?
It is the surface to surface properties which are important. The actual
static friction is proportional to the load, so halving it and using two
points will likely give a very similar result. However, if you put a fixed
vertical load on a ball resting on two rods, the loads at the two points are
increased to give the same resolved vertical force.
When we talk about friction in pendulum suspensions, it is not this
static friction to which we are referring. It is the tiny rolling contact loss as
the materials are compressed and relaxed. No materials are perfectly
elastic. Glass is poor in this respect and tends to chip easily.
Regards,
Chris
In a message dated 12/11/2007, tchannel1@............ writes:
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Hi Folks, Just wondering abou=
t=20
materials for roller on roller or balls on plates. I know the=20
limitations of glass, but a question about its smoothness, is the surface=20=
of=20
glass as smooth or smoother than these hardened and polished=20
steels?
Hi Ted,
Probably about the same. You get an optical fin=
ish=20
with fine polish on metal. However glass is a rapidly solidified liquid.
<=
FONT=20
style=3D"BACKGROUND-COLOR: transparent" face=3DArial color=3D#000000 size=
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My second question is one of friction: If=
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have one ball on one plate you would have one point of friction. If=20=
you=20
have one ball resting between two rollers, (in the V) you would=20=
have=20
two points of friction, but the load would be divided, because its resting=
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two points, so is the end result of friction loss the=20
same?
It is the surface to surface properties which a=
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important. The actual static friction is proportional to the load, so=20
halving it and using two points will likely give a very similar result. Howe=
ver,=20
if you put a fixed vertical load on a ball resting on two rods, the loa=
ds=20
at the two points are increased to give the same resolved vertical=20
force.
When we talk about friction in pendulum=20
suspensions, it is not this static friction to which we are referring. It is=
the=20
tiny rolling contact loss as the materials are compressed and relaxed. No=20
materials are perfectly elastic. Glass is poor in this respect and tends to=20=
chip=20
easily.
Regards,
Chris
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