Hi Folks,  With some help from many of you, I understand how one loses =
the signals LONGER than your sensor natural period.  ie  If you sensors =
period is 10 seconds it will lose  (attenuate) the longer frequencies at =
a rate of 12 decibels per octave.   I think I understand that part. =20

But want about the opposite, say the sensors is 10 second, how does it =
lose or does it lose shorter frequencies, like 2, 4 or 6 seconds waves?

My new Lehman is set at 20 seconds, will it pick up 1, 2, and 3 seconds =
waves?








Hi Folks,  With some help from =
many of you, I=20
understand how one loses the signals LONGER than your sensor natural=20
period.  ie  If you sensors period is 10 seconds it will =
lose =20
(attenuate) the longer frequencies at a rate of 12 decibels per=20
octave.   I think I understand that part.  
 
But want about the opposite, say the =
sensors is 10=20
second, how does it lose or does it lose shorter frequencies, like 2, 4 =
or 6=20
seconds waves?
 
My new Lehman is set at 20 seconds, =
will it pick up=20
1, 2, and 3 seconds waves?
 
Thanks, Ted