PSN-L Email List Message
Subject: Re: Integrating in WinQuake
From: ChrisAtUpw@.......
Date: Mon, 23 Nov 2009 21:09:20 EST
In a message dated 23/11/2009, rsparks@.......... writes:
There seems to be an ongoing difference of opinion of what constitutes a
velocity detector or an acceleration detector. To my mind, if a
seismometer automatically returns to a zero position, then it must be
recording acceleration. All vertical seismometers do this because they
all are measuring against gravity, so they would all be acceleration
devices. Excepting the sensitivity to tilt, all horizontal seismometers
also return to a zero position so they could also be called acceleration
sensitive devices. But maybe this description oversimplifies the
situation.
Hi Roger,
Sorry, but no. You seem to be confusing devices which have AC and DC
characteristics.
Some sensors (capacitive and optical for example) clearly record
displacement (neither acceleration or velocity).
Agreed.
On the other hand, with magnetic/coil devices, velocity is always observed
when electrical
output is observed so magnetic/coil devices are velocity detectors.
No. They may be either velocity or acceleration detectors. If the coil
is attached to a ~freely suspended, but damped, mass, you get a velocity
detector - eg a Lehman. If it is attached to a mass suspended on a spring,
you get an acceleration detector. The length of the spring is constant if
the velocity is constant. It only changes in length and causes the coil to
move if there is an acceleration.
A displacement sensor would record the relative distance from a some zero
point at the instant of data read, the velocity sensor would record the
relative velocity at the instant of data read, and acceleration sensor
would
detect the acceleration! eg a MEMs acclerometer.
be a calculated number found by using the data from any two velocity
data points and any three displacement data points.
Agreed.
Finally, if two seismometers, identical except for detectors, were
placed side by side, they would both plot the identical earthquake wave
form, assuming that the frequency characteristics were the same.
No, they wouldn't. A velocity output is proportional to the
differential (slope) of a position output plot with time.
However, when it is recognized that displacement position is not time
sensitive but velocity is, the builder can expect dramatic frequency
response differences between displacement detectors and velocity
detectors . Simply put, distance is distance, but velocity is the
distance divided by the time needed to travel between two points. As a
result, for velocity detectors, the longer the wave length, the less
energy for each instant resulting in decreased voltage (and current)
detected at each instant (for any defined magnetic field).
Regards,
Chris Chapman
In a message dated 23/11/2009, rsparks@.......... writes:
There=20
seems to be an ongoing difference of opinion of what constitutes a=20
velocity detector or an acceleration detector. To my mind, if=
a=20
seismometer automatically returns to a zero position, then it must=
be=20
recording acceleration. All vertical seismometers do this beca=
use=20
they
all are measuring against gravity, so they would all be acceler=
ation=20
devices. Excepting the sensitivity to tilt, all horizontal=20
seismometers
also return to a zero position so they could also be ca=
lled=20
acceleration
sensitive devices. But maybe this description=20
oversimplifies the situation.
Hi Roger,
Sorry, but no. You seem to be confusing=
=20
devices which have AC and DC characteristics.
Some=20
sensors (capacitive and optical for example) clearly record
displace=
ment=20
(neither acceleration or velocity).
Agreed.
On the=20
other hand, with magnetic/coil devices, velocity is always observed when=
=20
electrical
output is observed so magnetic/coil devices are velocity=
=20
detectors.
No. They may be either velocity or accelerati=
on=20
detectors. If the coil is attached to a ~freely suspended, but damped, mas=
s, you=20
get a velocity detector - eg a Lehman. If it is attached to a mass suspend=
ed on=20
a spring, you get an acceleration detector. The length of the spring is co=
nstant=20
if the velocity is constant. It only changes in length and causes the coil=
to=20
move if there is an acceleration.
A=20
displacement sensor would record the relative distance from a some zero=
=20
point at the instant of data read, the velocity sensor would record=
the=20
relative velocity at the instant of data read, and acceleratio=
n=20
sensor would
detect the acceleration! eg a MEMs=20
acclerometer.
be a=20
calculated number found by using the data from any two velocity
data=
=20
points and any three displacement data points.
Agreed.
Finally,=20
if two seismometers, identical except for detectors, were
placed sid=
e by=20
side, they would both plot the identical earthquake wave
form, assum=
ing=20
that the frequency characteristics were the same.
No, they wouldn't. A velocity output is=20
proportional to the differential (slope) of a position output plot with=20
time.
However, when it is recognized that displacement posi=
tion is=20
not time
sensitive but velocity is, the builder can expect dramatic=
=20
frequency
response differences between displacement detectors and ve=
locity=20
detectors . Simply put, distance is distance, but velocity is=
the=20
distance divided by the time needed to travel between two=20
points. As a
result, for velocity detectors, the longer=
the=20
wave length, the less
energy for each instant resulting in decreased=
=20
voltage (and current)
detected at each instant (for any defined magn=
etic=20
field).
Regards,
Chris Chapman
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