Brett, thank you so very much for that invaluable information...Beautifully= =0Aclear terms! Also I would like to recommend this incredible PDF to the = group....=0A=0A=0A=0A=0A________________________________=0AFrom: Brett Nord= gren=0ATo: psnlist@...................... Sun, May= 1, 2011 12:52:02 PM=0ASubject: Re: Possible Spring To Use=0A=0AGeoff,=0A= =0AAt 10:35 AM 5/1/2011, you wrote:=0A> Why must that be ?=0A> =0A> Noteboo= k paper is only 0.003"=0A> Why must a spring be so thin ?=0A=0AWhen you ben= d a leaf spring into the sort of curve that you want for typical =0Aseismo = designs, if the spring is too thick it will be stressed beyond its yield = =0Astrength and it will get bent into a permanent curve--not good.=0A=0AThe= relationship is: Radius =3D E x Thickness / (2 x Stress)=0Aor Thickness = =3D 2 x Stress x Radius / E=0A=0AWhere E is the Elastic Modulus - Assume 32= E6 psi for steel=0AYield Stress is well over 200,000 psi for good spring st= eel, so a safe design =0Astress level might be 150,000 psi=0A=0AFor a minim= um bend radius of 1 inch, which is about what we see in a 9" long =0Ainstru= ment, you have: Thickness =3D 2 x 150,000 x 1 / 32E6 =3D 0.0094" maximum.= =A0 =0AThicker than that and the stress will exceed 150,000 psi.=A0 Smaller= designs will =0Arequire thinner springs.=0A=0A> Also,=0A> =0A> This Zero L= ength spring stuff ?=0A> =0A> Do I understand right when I think=0A> a zero= length spring does not change force as the spring length changes ?=0A=0ANo= , it acts pretty much like any other coil spring, only that it is pre-stres= sed =0Aso that the force needed to make it begin to stretch is exactly the = right =0Avalue.=A0 Then, *if and only if*, that spring is used with the LaC= oste pendulum =0Ageometry, you get an 'infinite' period.=0A=0ASimilar resul= ts may be obtained with astatic leaf spring designs, however 'zero =0Alengt= h' only applies to LaCoste coil springs.=0A=0AAlthough having an infinite p= eriod pendulum sounds attractive, it has the great =0Aproblem that tiny tem= perature changes will make the boom drift off to the stop.=A0 =0AYou will w= ant to give the boom at least a small tendency to center itself, which =0Am= eans that it will have a non-infinite period.=0A=0AFeedback designs pretty = much eliminate that issue.=0A=0ARegards,=0ABrett =0A=0A____________________= ______________________________________=0A=0APublic Seismic Network Mailing = List (PSNLIST)=0A=0ATo leave this list email PSNLIST-REQUEST@............... with the body of the =0Amessage (first line only): unsubscribe=0ASee http:= Brett, thank you so very much for that invaluable information..= ..Beautifully clear terms! Also I would like to recommend this incredible PD= F to the group....=0A=
=0A=0A
=0AFrom: Brett Nord= gren <brett3nt@.............>
To: psnlist@..............
Sent: Sun, May 1, 2011 12:52:02 PM
Subject: Re: Possible Spring To Use
Geoff,
At 10:35 AM 5/1/2011, you wrote:
> Why must that be ?<= BR>>
> Notebook paper is only 0.003"
> Why must a spring be= so thin ?
When you bend a leaf spring into the sort of curve that y= ou want for typical seismo designs, if the spring is too thick it will be s= tressed beyond its yield strength and it will get bent into a permanent cur= ve--not good.
The relationship is: Radius =3D E x Thickness / (2 x S= tress)
or Thickness =3D 2 x Stress x Radius / E
Where E is the El= astic Modulus - Assume 32E6 psi for steel
Yield Stress is well over 200,= 000 psi for good spring steel, so a safe design stress level might be 150,000 psi
Fo= r a minimum bend radius of 1 inch, which is about what we see in a 9" long = instrument, you have: Thickness =3D 2 x 150,000 x 1 / 32E6 =3D 0.0094" maxi= mum. Thicker than that and the stress will exceed 150,000 psi. = Smaller designs will require thinner springs.
> Also,
>
> This Zero Length spring stuff ?
>
> Do I understand righ= t when I think
> a zero length spring does not change force as the sp= ring length changes ?
No, it acts pretty much like any other coil sp= ring, only that it is pre-stressed so that the force needed to make it begi= n to stretch is exactly the right value. Then, *if and only if*, that= spring is used with the LaCoste pendulum geometry, you get an 'infinite' p= eriod.
Similar results may be obtained with astatic leaf spring desi= gns, however 'zero length' only applies to LaCoste coil springs.
Although having an infinite period pendulum sounds attract= ive, it has the great problem that tiny temperature changes will make the b= oom drift off to the stop. You will want to give the boom at least a = small tendency to center itself, which means that it will have a non-infini= te period.
Feedback designs pretty much eliminate that issue.
Regards,
Brett
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