PSN-L Email List Message
Subject: Re: New Seismo
From: Pete Rowe ptrowe@.........
Date: Mon, 25 Jul 2011 15:38:00 -0700 (PDT)
Hi Dave=0AMy little seismometer has about 2 ounces of lead. =0A=0A=0AI use =
a resistor across the coil as the damper. Put a 1k ohm pot across the coil =
and then check for the damping factor per Chris Chapman's recent post. Adju=
st the pot until you have critical damping and you are done.=0A=0A73,=0APet=
e=0A=0A=0A=0A________________________________=0AFrom: Dave Nelson =0ATo: psnlist@...................... Monday, July 25, =
2011 2:41 PM=0ASubject: RE: New Seismo=0A=0A=0AHi Randy,=0A=A0=A0=A0=A0=A0=
=A0=A0=A0=A0=A0=A0=A0=A0=A0=0Aahhh now there's some words of wisdom that I =
hadnt thought about =0Abefore. hmmm but the balance point would be probably=
right at the=0Aweights.=0AThe other seismo's I have seen online=A0 Chris C=
's one that I have=0Asorta copied,=0Athe SEP, and others, the support wires=
have been some distance back from=0Athe =0Aweights.=A0=A0 Out of curiosity=
how much weight do you have on your=0Aone ?=0Awhat are other guys using ?=
=A0=A0 Gosh I was thinking 4 pounds was=0Anowhere near =0Aenough and would =
have preferred almost twice that amount.=A0 Thats=0Aconsidering the=0A=A0Sp=
rengnether I had in NZ had ~28 lbs os mass.=0A=0AAll that being said I coul=
d still take the support wires to the other end=0Aof the frame =0Aholding t=
he coil magnets and gain a bit more ib the balancing act=A0=0A:)=0A=0Aspeak=
up all=A0=A0 what weights are commonly being used ? and how=0Amany of you=
=0Aconsidered the balance point of the boom when adding the support wires=
=0A?=0A=0Acheers=0ADave=0A=0A=0AAt 12:17 AM 26/07/2011, you wrote:=0A=0AHi=
=0ADave,=0A>If you remove the boom and find the balance point of the boom y=
ou can=0Are-attach the support wire at or very near that point.=A0 This wil=
l=0Aremove the vertical force on the pivot and allow it to sit in=0Aplace.=
=A0 Another option would be to remove one weight.=A0 Removing=0Athe weight =
would also help to increase the damping effect.=A0 With 4=0Apounds of weigh=
t in my experience you will not get enough damping with=0Athe 1 small magne=
Hi Dave
My little seismometer has about 2 ounces of lead.
=
I use a resistor across=
the coil as the damper. Put a 1k ohm pot across the coil and then check fo=
r the damping factor per Chris Chapman's recent post. Adjust the pot until =
you have critical damping and you are done.
73,
Pete
=
div>
From: Dave Nelson <dave.ne=
lson@...............>
To:
psnlist@..............
Sent: Monday, July 25, 2011 2:41 PM
Subject: RE: New Seismo
=0AHi Randy,
=0A  =
; =0Aahhh now there's some words of wisdom tha=
t I hadnt thought about
=0Abefore. hmmm but the balance point would be =
probably right at the=0Aweights.
=0AThe other seismo's I have seen onlin=
e Chris C's one that I have=0Asorta copied,
=0Athe SEP, and others=
, the support wires have been some distance back from=0Athe
=0Aweights.=
Out of curiosity how much weight do you have on your=0Aone ?
=0Awhat are other guys using ? Gosh I was thinking 4 pounds w=
as=0Anowhere near
=0Aenough and would have preferred almost twice that =
amount. Thats=0Aconsidering the
=0A Sprengnether I had in NZ =
had ~28 lbs os mass.
=0AAll that being said I could still take the s=
upport wires to the other end=0Aof the frame
=0Aholding the coil magnet=
s and gain a bit more ib the balancing act =0A:)
=0Aspeak up al=
l what weights are commonly being used ? and how=0Amany of you<=
br>=0Aconsidered the balance point of the boom when adding the support wire=
s=0A?
=0Acheers
=0ADave
=0A
=0AAt 12:17 AM 26/07/2011, =
you wrote:
=0AHi=0ADave,
=0AIf you remove the bo=
om and find the balance point of the boom you can=0Are-attach the support w=
ire at or very near that point. This will=0Aremove the vertical force=
on the pivot and allow it to sit in=0Aplace. Another option would be=
to remove one weight. Removing=0Athe weight would also help to incre=
ase the damping effect. With 4=0Apounds of weight in my experience yo=
u will not get enough damping with=0Athe 1 small magnet.
=0ARandall L.=0APratt
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