Hi Chris,

Just to be clearer, what I said below represented the geophone 
response as output current vs input voltage (analog of velocity).  It 
assumed that the output was shorted and output current was being measured.

>Indeed, the model shows a +1 slope in the velocity response (flat to 
>acceleration) from about 0.65Hz to around 50Hz.  The electronics 
>integrates that to get a flat velocity response over that frequency range.

Brett



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